2 x² + 5 x - 2 = 0
(menggunakan rumus abc)![]()
(menggunakan rumus abc)
Jawaban:
Persamaan Kuadrat
a = 2
b = 5
c = -2
[tex]x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
[tex]x = \frac{ - 5± \sqrt{ {5}^{2} - (4 \times 2 \times - 2)} }{2 \times 2} [/tex]
[tex]x = \frac{ - 5± \sqrt{25 - - 16} }{4} [/tex]
[tex]x = \frac{ - 5± \sqrt{41} }{4} [/tex]
[tex]x1 = \frac{ - 5+ \sqrt{41} }{4} [/tex]
[tex]x2 = \frac{ - 5 - \sqrt{41} }{4} [/tex]
Penjelasan dengan langkah-langkah:
- Rumus ABC :
- a = 2
- b = 5
- c = -2
- Penyelesaian :
[tex] x= 2a−b± b 2 −4acx = \frac{ - 5\sqrt{ {5}^{2} - (4 \times 2 \times - 2)} }{2 \times 2}x= 2×2−5± 5 2 −(4×2×−2)x = \frac{ - 5± \sqrt{25 - - 16} }{4}x= 4−5± 25−−16x = \frac{ - 5± \sqrt{41} }{4}x= 4−5± 41x1 = \frac{ - 5+ \sqrt{41} }{4}x1= 4−5+ 41x2 = \boxed{\red{\frac{ - 5 - \sqrt{41} }{4}}}[/tex]
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